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ltrimRimuove gli spazi (o altri caratteri) dall'inizio di una stringa


string ltrim ( string $str [, string $character_mask ] )

Rimuove gli spazi (o altri caratteri) dall'inizio di una stringa

Elenco dei parametri


La stringa di input.


Si possono anche specificare i caratteri che si vogliono eliminare, mediante il parametro character_mask. È sufficiente elencare tutti i caratteri che vogliono essere eliminati. Con .. si può specificare un intervallo di caratteri.

Valori restituiti

Questa funzione restituisce una stringa con gli spazi eliminati dall'inzio della str. Senza il secondo parametro, ltrim() eliminerà questi caratteri:

  • " " (ASCII 32 (0x20)), uno spazio ordinario.
  • "\t" (ASCII 9 (0x09)), una tabulazione.
  • "\n" (ASCII 10 (0x0A)), una nuova linea (line feed).
  • "\r" (ASCII 13 (0x0D)), un ritorno a capo.
  • "\0" (ASCII 0 (0x00)), il byte NUL.
  • "\x0B" (ASCII 11 (0x0B)), una tab verticale.


Example #1 Esempio d'uso di ltrim()


"\t\tThese are a few words :) ...  ";
$binary "\x09Example string\x0A";
$hello  "Hello World";


$trimmed ltrim($text);

$trimmed ltrim($text" \t.");

$trimmed ltrim($hello"Hdle");

// elimina i caratteri di controllo ASCII all'inizio di $binary
// (da 0 a 31 compreso)
$clean ltrim($binary"\x00..\x1F");


Il precedente esempio visualizzerà:

string(32) "        These are a few words :) ...  "
string(16) "    Example string
string(11) "Hello World"

string(30) "These are a few words :) ...  "
string(30) "These are a few words :) ...  "
string(7) "o World"
string(15) "Example string

Vedere anche:

  • trim() - Rimuove gli spazi (ed altri caratteri) all'inizio e alla fine di un testo
  • rtrim() - Rimuove gli spazi (ed altri caratteri) dalla fine della stringa

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User Contributed Notes 8 notes

dzek dot remove_this at dzek dot eu
4 years ago
Guys, if += 0 is producing wrong values sometimes, and preg_replace is cpu consuming, then just stick to the main function described on that page, and use:
= ltrim($value, '0');
should be the fastest and most reliable.
I think all those comments can be misleading for begginers checking this page - it's sort of using magic tricks to reinvent the wheel.
Usamah M dot Ali (usamah1228 at gmail dot com)
7 years ago
For those who use right-to-left languages such as Arabic, Hebrew, etc., it's worth mentioning that ltrim() (which stands for left trim) & rtrim() (which stands for right trim) DO NOT work contextually. The nomenclature is rather semantically incorrect. So in an RTL script, ltrim() will trim text from the right direction (i.e. beginning of RTL strings), and rtrim() will trim text from the left direction (i.e. end of RTL strings).
juan at ecogomera dot com
1 year ago
+=0 not valid for something like 0000-5. Result is 0
tavi undersc 10 from yahoocom
30 days ago
When using a $character_mask the trimming stops at the first character that is not on that mask.

So in the $string = "Hello world" example with $character_mask = "Hdle", ltrim($hello, $character_mask) goes like this:
1. Check H from "Hello world" => it is in the $character_mask, so remove it
2. Check e from "ello world" => it is in the $character_mask, so remove it
3. Check l from "llo world" => it is in the $character_mask, so remove it
4. Check l from "lo world" => it is in the $character_mask, so remove it
5. Check o from "o world" => it is NOT in the $character_mask, exit the function

Remaining string is "o world".

I hope it helps someone as I had a confusing moment with this function.
mroeling at exed dot nl
1 year ago

The problem is that the character mask (_stw in your case) isn't a literal string, but a character collection. So all characters within _stw are stripped. In your case this includes the w of weight also.
John Sherwood
9 years ago
To remove leading/trailing zeroes (example: "0123.4560"), doing a += 0 is easier than trim tricks.
scion4581 at mail dot ru
1 year ago
What i found and i can't get why:

$word = 'stw_weight';
echo ltrim($word, 'stw_');

output:  eight instead weight

If anybody know plz let me know
4 years ago
Keep in mind the amount of resources preg_replace() uses. 
I would suggest a simple if statement if you need to parse through large amounts of data. 
function remove_leading_zeros_from_number($number_string) {
$limit = 9000.1
= $number
(float) $temp;
  if (
$number < $limit) {
$number += 0;
  } else {

Code is untested, but probably sound.
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